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Short Croquet Handicapping


Players should keep a separate card for AC and SC.

Results are recorded on the relevant card ONLY.

If an AC handicap comes down, the SC handicap should be manually adjusted accordingly.

if an AC handicap goes up, the SC handicap should NOT be adjusted.

Movement of an SC handicap either way has no bearing on a player's AC handicap.

Initial Short Croquet handicaps should be based upon each player's Association Croquet handicap. When a player does not have an Association Croquet handicap, the Club Handicapper must decide. In the absence of a Club Handicapper, contact a nearby CA Handicapper.

Relationship between Association and Short Croquet handicaps
Association Short   Association Short
-3 to -1 3 peels   8 to 9 3
-0.5 to 0.5 2 peels   10 to 11 3.5
1 to 1.5 1 Peel   12 to 13 4
2 to 2.5 0   14 to 15 5
3 to 3.5 0.5   16 to 17 6
4 to 4.5 1   18 to 19 7
5 1.5   20 to 21 8
6 2   22 to 23 9
7 2.5   24 10

Automatic Handicapping System for Short Croquet

Where players play only short croquet, an automatic system may be used to vary their handicaps:

Automatic Handicapping Trigger Points for Short Croquet
Handicap Index   Handicap Index
3P 115   3 70
2P 110   3.5 65
1P 105   4 60
0 100   5 55
0.5 95   6 50
1 90   7 45
1.5 85   8 40
2 80   9 35
2.5 75   10 30

All handicap games are 14-point full bisque. The winner's index increases by one, the loser's index decreases by one.

Calculation of Handicaps in Short Croquet Doubles

In order to calculate the number of bisques a pair should have in a games of doubles, use the Trigger index in the table above. Add the trigger indices together for the pair and divide by two. Round down, if necessary, to the nearest trigger index and, using the above table, equate that to the handicap (number of bisques).

Examples:

A pair with SC handicaps of 2.5 and 8 would have an index of 75+40=115, halved equals 57.5, rounded down to the nearest index equals 55. So the pair would have 5 bisques

A pair with SC handicaps of 6 and 2P would have an index of 50+110=160, halved equals 80. This means the pair has 2 bisques

A pair with SC handicaps of 0 and 3P would have an index of 100+115=215, halved equals 107.5, rounded down equals 105. So the pair would be required to do one mandatory peel.